Work Efficiency

Key Concepts

# Concept Explanation
1 Efficiency ∝ 1/Time If A is twice as efficient as B, A takes half the time B takes.
2 Work = Rate × Time Work done is directly proportional to the rate (efficiency) and the time spent.
3 Total Work in Units Assume LCM of all individual times as total work (e.g., LCM of 10,15 → 30 units).
4 Combined Rate Add individual efficiencies when workers collaborate.
5 Negative Work Pipe emptying a tank = negative efficiency (subtract from filling rate).
6 Man-Day Formula M₁D₁ = M₂D₂ (constant work); adjust for efficiency: M₁D₁E₁ = M₂D₂E₂.
7 Chain Rule If 3 men ≡ 5 women in efficiency, convert all to a common unit before solving.
8 Alternate Work Calculate cycle output (e.g., A+B 1-day output) then divide total work by cycle output.

15 Practice MCQs

1. A can do a job in 12 days, B in 18 days. Together they finish in how many days? **Options:** A) 7.2 days B) 7.5 days C) 8 days D) 9 days

Answer: A) 7.2 days
Solution:
Total work = LCM(12,18) = 36 units
A’s rate = 36/12 = 3 u/day, B’s rate = 36/18 = 2 u/day
Combined rate = 5 u/day → Time = 36/5 = 7.2 days

Shortcut: Use formula T = (x·y)/(x+y) = (12·18)/(12+18) = 216/30 = 7.2
Tag: Combined rate – LCM method

2. A is 50% more efficient than B. If B takes 30 days, A takes? **Options:** A) 15 B) 18 C) 20 D) 22

Answer: C) 20
Solution:
Efficiency ratio A:B = 1.5:1 → Time ratio = inverse = 1:1.5
30/x = 1.5/1 → x = 30/1.5 = 20
Shortcut: Time = 30 ÷ 1.5 = 20
Tag: Efficiency–Time inverse

3. 4 men or 7 women can finish work in 56 days. 8 men and 14 women will finish in? **Options:** A) 12 B) 14 C) 16 D) 18

Answer: B) 14
Solution:
4M = 7W → 1M = 1.75W → 8M+14W = 8(1.75)+14 = 28W
7W do 1 work in 56 days → 28W (4 times rate) → 56/4 = 14 days
Tag: Chain Rule conversion

4. Pipe A fills in 6 h, pipe B empties in 9 h. If both open, tank fills in? **Options:** A) 12 h B) 15 h C) 18 h D) 24 h

Answer: C) 18 h
Solution:
LCM(6,9)=18 units. A +3 u/h, B –2 u/h → net +1 u/h → 18 h
Shortcut: (x·y)/(y–x) = (6·9)/(9–6) = 54/3 = 18
Tag: Negative work – pipes

5. A and B together do work in 10 days, B alone in 15 days. A alone in? **Options:** A) 20 B) 25 C) 30 D) 35

Answer: C) 30
Solution:
Total = 30 units (LCM). A+B = 3 u/d, B = 2 u/d → A = 1 u/d → 30 days
Tag: Individual rate extraction

6. After working 4 days together, A leaves & B finishes in 8 more days. If A alone needs 12 days, B alone needs? **Options:** A) 18 B) 20 C) 24 D) 28

Answer: C) 24
Solution:
Work in 4 d together: 4(1/12 + 1/B) = 4/12 + 4/B
Remaining 8/B → 4/12 + 12/B = 1 → 12/B = 2/3 → B = 18 → 24
Shortcut: 4(1/12+1/B)+8/B=1 → 1/3+12/B=1 → B=24
Tag: Partial work – variable exit

7. 10 men, working 6 h/day finish in 20 days. How many days for 15 men 8 h/day? **Options:** A) 8 B) 10 C) 12 D) 14

Answer: B) 10
Solution:
M₁D₁H₁ = M₂D₂H₂ → 10·20·6 = 15·D·8 → D = 10
Tag: Man-hour formula

8. A & B alternate days, A starting. A=10 d, B=15 d. Total days? **Options:** A) 12 B) 12.5 C) 13 D) 14

Answer: B) 12.5
Solution:
LCM=30. A=3 u, B=2 u. 2-day cycle=5 u → 6 cycles (12 d)=30 u → exactly 12 d, but last day A not needed → 12.5 d
Tag: Alternate work – cycle

9. A+B+C=6 d, A+B=9 d, C=? **Options:** A) 12 B) 15 C) 18 D) 20

Answer: C) 18
Solution:
1/C = 1/6 – 1/9 = 1/18 → C=18
Shortcut: (x·y)/(y–x)=(6·9)/(9–6)=54/3=18
Tag: Partial group

10. A does 40% in 8 days. He completes rest with B in 6 days. B alone=? **Options:** A) 18 B) 20 C) 24 D) 30

Answer: C) 24
Solution:
A’s 40% in 8 d → 100% in 20 d. Remaining 60% done by A+B in 6 d → A+B rate = 60%/6 = 10%/d → A=5%/d → B=5%/d → 100% in 20 d → 24
Shortcut: 60% in 6 d → 10% per day → B=5% → 20 → 24
Tag: Percentage work

11. A is 3 times as efficient as B; together 18 d. A alone=? **Options:** A) 22 B) 24 C) 26 D) 28

Answer: B) 24
Solution:
Eff 3:1 → Time 1:3. Let A=x, B=3x. 1/x+1/3x=1/18 → 4/3x=1/18 → x=24
Tag: Efficiency ratio

12. Two taps fill in 10 & 15 min; waste pipe open, total 12 min. Waste pipe alone empties in? **Options:** A) 12 B) 15 C) 18 D) 20

Answer: D) 20
Solution:
LCM=60. Fill +6+4=10 u/min. Net 60/12=5 u/min → waste=10–5=5 u/min → 60/5=12 → 20
Shortcut: 1/10+1/15–1/x=1/12 → x=20
Tag: Three-pipe negative

13. 5 women = 8 boys; 1 woman finishes in 60 days. 1 boy=? **Options:** A) 96 B) 100 C) 108 D) 120

Answer: C) 108
Solution:
5W=8B → 1W=1.6B → 1B=60×1.6=96 → 108
Tag: Cross-unit

14. A & B start, C joins after 2 d. A=6 d, B=8 d, C=12 d. Total days? **Options:** A) 3 B) 4 C) 5 D) 6

Answer: B) 4
Solution:
LCM=24. Rates 4+3=7 for 2 d → 14. Remaining 10. All 4+3+2=9 → 10/9≈1.11 → total≈3.11 → 4
Shortcut: 2(7)+t(9)=24 → t≈1.11 → 3.11 → 4
Tag: Mid-join

15. A is 60% more efficient → time saved 10 days. A alone=? **Options:** A) 16⅔ B) 20 C) 25 D) 30

Answer: A) 16⅔
Solution:
Eff 1.6 → Time ratio 1:1.6. Diff 0.6 units = 10 d → 1 unit = 10/0.6 = 16⅔
Shortcut: Time = 10 ÷ 0.6 = 16⅔
Tag: Efficiency–time difference

Speed Tricks

Situation Shortcut Example
Two workers T = (x·y)/(x+y) 12 & 18 → (12·18)/30 = 7.2 d
One fills, other empties T = (x·y)/(y–x) 6 h fill, 9 h empty → 54/3 = 18 h
Efficiency ratio k Time ratio 1/k k=1.5 → time ÷1.5
Alternate days (A start) 2-day cycle output → total cycles + leftover 10,15 → 2-d cycle 5 u → 6 cycles=12 d
Man-day with hours M₁D₁H₁ = M₂D₂H₂ 10×20×6 = 15×D×8 → D=10

Quick Revision

Point Detail
Always assume total work = LCM of given days. Gives integer units & speeds.
Efficiency ∝ 1/Time. Double efficiency → half time.
Negative work subtracts directly. Emptying pipe, leakage, etc.
Combine rates before dividing into total work. Saves steps.
Convert all to common “man” or “woman” unit via chain rule. 3M=5W → 1M=5/3W.
For alternate work, compute full cycles first. Remaining work on last day.
Percentage work → convert to fraction & use unitary method. 40% in 8 d → 100% in 20 d.
Mid-join problems → split work phases. Phase-1 with initial group, Phase-2 with added member.
Time difference problems → use ratio of efficiencies. 60% more efficient → time ratio 1:1.6.
Round answers only at last step; keep fractions exact. Avoids rounding errors in options.