Light Reflection Refraction

Key Concepts

# Concept Explanation
1 Law of Reflection Angle of incidence (∠i) = Angle of reflection (∠r); incident ray, reflected ray & normal lie in same plane.
2 Spherical Mirrors Concave → converges light; Convex → diverges light; pole (P), focus (F), centre of curvature (C), radius (R), focal length (f) = R/2.
3 Mirror Formula 1/f = 1/v + 1/u (Cartesian sign: real −ve, virtual +ve); magnification m = –v/u.
4 Refraction Bending of light when it passes obliquely from one medium to another; governed by Snell’s law: n₁ sin i = n₂ sin r.
5 Refractive Index (n) n = c/v (speed in vacuum ÷ speed in medium); n > 1 for denser medium; n = real depth ÷ apparent depth.
6 Critical Angle (θc) sin θc = n₂/n₁ (n₁ > n₂); beyond θc total internal reflection (TIR) occurs—basis of optical fibre.
7 Lens Formula Same as mirror formula but f is +ve for convex & −ve for concave; power P (D) = 1/f (metre).
8 Prism & Dispersion White light splits into VIBGYOR because n varies with λ (violet deviates most, red least).

15 Practice MCQs

1. A ray of light strikes a plane mirror at 30° to the mirror surface. The angle of reflection is A) 30° B) 60° C) 90° D) 0°

Answer: B) 60°
Solution: Angle to normal = 90° – 30° = 60° = ∠i ⇒ ∠r = 60°.
Shortcut: Always drop perpendicular; angle with normal decides.
Tag: Law of reflection

2. The radius of curvature of a concave mirror is 40 cm. Its focal length is A) 40 cm B) 20 cm C) 80 cm D) 10 cm

Answer: B) 20 cm
Solution: f = R/2 = 40/2 = 20 cm.
Shortcut: Remember “f is half R” for mirrors.
Tag: Spherical mirror

3. An object is placed 15 cm in front of a concave mirror of f = 10 cm. The image is A) virtual & erect B) real & inverted C) real & erect D) virtual & inverted

Answer: B) real & inverted
Solution: u = –15 cm, f = –10 cm ⇒ 1/v = 1/f – 1/u = –1/10 + 1/15 = –1/30 ⇒ v = –30 cm (real).
Shortcut: If |u| > |f| & concave → real.
Tag: Mirror formula

4. Speed of light in medium is 2 × 10⁸ m s⁻¹. Refractive index of medium is A) 1.0 B) 1.33 C) 1.5 D) 2.0

Answer: C) 1.5
Solution: n = c/v = 3×10⁸ / 2×10⁸ = 1.5.
Shortcut: n = 3 ÷ (speed in 10⁸) gives quick value.
Tag: Refractive index

5. A coin at bottom of 6 cm water (n = 4/3) appears at depth A) 8 cm B) 4.5 cm C) 6 cm D) 3 cm

Answer: B) 4.5 cm
Solution: Apparent depth = real depth / n = 6 / (4/3) = 4.5 cm.
Shortcut: Multiply real depth by 0.75 (≈ 3/4) for water.
Tag: Apparent depth

6. Critical angle for glass-air interface (n_glass = 1.5) is about A) 30° B) 42° C) 60° D) 90°

Answer: B) 42°
Solution: sin θc = 1/1.5 = 0.666 ⇒ θc ≈ 42°.
Shortcut: Rough inverse of n gives angle; 1.5 → ~42°.
Tag: Critical angle

7. Which colour travels slowest in glass? A) Red B) Yellow C) Violet D) Green

Answer: C) Violet
Solution: Higher n for shorter λ ⇒ violet bends most & speed = c/n least.
Shortcut: “Violet Viciously Slow”.
Tag: Dispersion

8. Power of a convex lens of f = 25 cm is A) +4 D B) +2.5 D C) +0.25 D D) –4 D

Answer: A) +4 D
Solution: P = 1/0.25 m = +4 D.
Shortcut: 100 ÷ cm gives D (100/25 = 4).
Tag: Lens power

9. A virtual, erect & magnified image is formed by A) concave mirror with object beyond C B) convex mirror C) concave mirror with object between F & P D) plane mirror

Answer: C) concave mirror with object between F & P
Solution: Only this range gives virtual, erect & |m| > 1.
Shortcut: “Inside F → virtual magnified shave mirror”.
Tag: Image characteristics

10. When light goes from air to diamond (n = 2.42) it A) bends away from normal B) bends towards normal C) does not bend D) reflects totally

Answer: B) bends towards normal
Solution: n increases ⇒ speed decreases ⇒ bends towards normal.
Shortcut: “Dense → Normal hug”.
Tag: Refraction direction

11. A diver inside water looks at the setting Sun; to him the Sun appears A) higher than real B) lower than real C) at real position D) invisible

Answer: A) higher than real
Solution: Light bends away from normal exiting water; diver extrapolates along bent ray → elevated image.
Shortcut: Always “bend away → looks high”.
Tag: Apparent position

12. An object is placed 20 cm from a convex mirror of f = 30 cm. Image distance is A) –12 cm B) +12 cm C) –7.5 cm D) +7.5 cm

Answer: B) +12 cm
Solution: 1/v = 1/f – 1/u = 1/30 – 1/(–20) = 1/30 + 1/20 = 5/60 ⇒ v = +12 cm (virtual).
Shortcut: For convex mirror v always +ve & < |f|.
Tag: Convex mirror

13. Magnification produced by plane mirror is always A) –1 B) +1 C) 0 D) ∞

Answer: B) +1
Solution: Image size = object size & erect ⇒ m = +1.
Shortcut: “Plane plain +1”.
Tag: Plane mirror

14. Optical fibres work on the principle of A) scattering B) diffraction C) total internal reflection D) interference

Answer: C) total internal reflection
Solution: Light trapped by repeated TIR along fibre.
Shortcut: “TIR → Fibre wire”.
Tag: Total internal reflection

15. A convex lens acts as a simple magnifying glass when object is placed A) at 2F B) at F C) between F & optical centre D) beyond 2F

Answer: C) between F & optical centre
Solution: Only here image virtual, erect & |m| > 1.
Shortcut: “Inside F → magnify”.
Tag: Magnifying glass


Speed Tricks

Situation Shortcut Example
Mirror focal length f = R ⁄ 2 (same unit) R = 60 cm ⇒ f = 30 cm
Apparent depth in water Multiply real depth by ¾ 8 cm water → looks 6 cm
Power from cm D = 100 ÷ cm 20 cm lens → 5 D
Critical angle quick θc ≈ 42° for n = 1.5 Glass-air
Lens / mirror sign “Real is Negative” Real image → v −ve, inverted → m −ve

Quick Revision

Point Detail
1 ∠i = ∠r & all three (incident, reflected, normal) are coplanar.
2 Concave mirror → converging; can give real/virtual image depending on object position.
3 Convex mirror always forms virtual, erect, diminished image—used as rear-view.
4 n = c/v; higher n ⇒ slower light & more bending towards normal.
5 Real depth > apparent depth; shift = t(1 – 1/n).
6 TIR possible only when light moves denser → rarer & ∠i > θc.
7 For lens, convex → +f & +P; concave → –f & –P.
8 Magnification
9 Violet has highest n & least speed in glass → deviates most.
10 Combine lenses: P_total = P₁ + P₂ (in dioptre).