RRB Technician 2014 Ques 8
Question: A conical tent of a diameter 24 m at the base and its height 16 m. The canvas required to make it is
Options:
A) $ \frac{5280}{7}m^{2} $
B) $ \frac{5180}{7}m^{2} $
C) $ \frac{4180}{7}m^{2} $
D) $ \frac{3480}{7}m^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
- Slant height $ =\sqrt{12^{2}+16^{2}} $ $ =\sqrt{400}=20m $ Canvas required = Curved surface area of conical tent $ =\pi rl=\frac{22}{7}\times 12\times 20 $ $ =\frac{5280}{7}m^{2} $
BETA
