RRB Technician 2014 Ques 33
Question: The maximum height is h to which a person can throw a ball. The maximum distance to which he can project it will be
Options:
A) $ h/2 $
B) h
C) $ 3h/2 $
D) 2h
Show Answer
Answer:
Correct Answer: D
Solution:
- In projectile motion, height $ h=\frac{u^{2}{{\sin }^{2}}\theta }{2g} $ For maximum h, $ \theta =90^{o} $ Maximum height $ =\frac{u^{2}}{2g}=h $ Maximum range is obtained when angle of projection is $ 45^{o} $ . Maximum range $ =\frac{u^{2}}{g}=2h $
BETA
