RRB Technician 2014 Ques 28
Question: A current of 5 A is flowing in a wire of length $ 1.5m $ . A force of $ 7.5N $ acts on it when it is placed in a uniform magnetic field of 2 tesla. The angle between the magnetic field and the direction of the current is
Options:
A) $ 60^{o} $
B) $ 90^{o} $
C) $ 30^{o} $
D) $ 45^{o} $
Show Answer
Answer:
Correct Answer: C
Solution:
- Bil $ \sin \theta =F\Rightarrow 2\times 5\times 1.5\sin \theta =7.5 $
$ \Rightarrow $ $ \sin \theta =\frac{7.5}{2\times 5\times 1.5}=\frac{1}{2}=\sin 30^{o} $
$ \therefore $ $ \theta =30^{o} $
BETA
