RRB Technician 2014 Ques 20
Question: The current flowing in a coil of self-inductance $ 0.4mH $ is increased by $ 250mA $ in $ 0.1s $ . The emf induced will be
Options:
A) $ -1,mV $
B) $ -1,V $
C) $ +1,mV $
D) $ +1,V $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ e=-\frac{di}{dt}=-0.4\times {10^{-3}}\times \frac{250\times {10^{-3}}}{0.1}=-1,mV $
BETA
