RRB Technician 2014 Ques 19
Question: An ideal transformer has 100 turns in the primary and 250 turns in the secondary. The peack value of the AC is 28 V. The rms secondary voltage is nearest to
Options:
A) 40 V
B) 100 V
C) 70 V
D) 50 V
Show Answer
Answer:
Correct Answer: D
Solution:
- $ \frac{V _2}{\frac{28}{\sqrt{2}}}=\frac{250}{100}\Rightarrow V _2=\frac{28\times 250}{\sqrt{2}\times 100}=\frac{14\times 5}{\sqrt{2}}=\frac{70}{1.41}\approx 50,V $
BETA
