RRB Technician 2013 Ques 21
Question: The emf of a primary cell is 2 V. When it is short-circuited, it gives a current of 4 A. Its internal resistance is
Options:
A) $ 2.0,\Omega $
B) $ 5.0,\Omega $
C) $ 0.5,\Omega $
D) $ 8.0,\Omega $
Show Answer
Answer:
Correct Answer: C
Solution:
- $ l=\frac{E}{r+R} $ When short circuited, external resistance = 0 $ 4=\frac{2}{r}\Rightarrow ,r=\frac{2}{4}=0.5,\Omega $
BETA
